1.HTML
<video id="video" autoplay class="fileImg"></video>
<canvas id="canvas" width="640" height="480"></canvas>
<div class="submitButton buttonData" @click="uploadImg">上传图片</div>
2.JS
<script>
let aVideo = document.getElementById(\'video\');
let aCanvas = document.getElementById(\'canvas\');
let ctx = aCanvas.getContext(\'2d\');
navigator.getUserMedia = navigator.getUserMedia ||
navigator.webkitGetUserMedia ||
navigator.mozGetUserMedia ||
navigator.msGetUserMedia; //获取媒体对象(这里指摄像头)
navigator.getUserMedia({
video: true
}, gotStream, noStream); //参数1获取用户打开权限;参数二成功打开后调用,并传一个视频流对象,参数三打开失败后调用,传错误信息
function gotStream(stream) {
video.src = URL.createObjectURL(stream);
video.onerror = function() {
stream.stop();
};
stream.onended = noStream;
video.onloadedmetadata = function() {
// alert(\'摄像头成功打开!\');
};
}
function noStream(err) {
// alert(err);
}
function uploadImg(){
ctx.drawImage(aVideo, 0, 0, 640, 480);
alert(aCanvas.toDataURL(\'image/png\')) // 得到base64,需要后台将base64转换并上传到服务器,返回线上http路径
const res = await fileUpload({imgStr: aCanvas.toDataURL(\'image/png\')}) // 调取后台接口
if (res.data.code == 0){
this.headImage = res.data.data.string //得到后台返回路径
}
}
</script>
