周记

这是本周学习的代码是让我们先定义一个日期结构体，结构成员包括年、月、日，然后建立通讯录结构体，结构体成员包括姓名、电话号码，之后再定义一雇员结构体，结构体成员包括：雇员姓名、职称、出生日期，通讯录（3个），最后输出。代码如下：

#include "stdafx.h"

#include "string.h"

#include "stdlib.h"

void OutPut(struct empl *ps, int n);

struct Date{

int year;

int month;

int day;

};

struct TongXunLu{

char name[20];

int tel;

struct empl{

char job[20];

struct Date bday;

struct TongXunLu Tx[3];

int main(int argc, char* argv[])

{

struct empl e1 = {"xiuzhe","shangxue",1937,12,12,"erwa",1234456,"goudang",12345,"tiezhu",345123};

OutPut(&e1,1);

empl e2;

strcpy(e2.name,"Peter");strcpy(e2.job,"shangke");

e2.bday.year=1945;e2.bday.month=11;e2.bday.day=23;

strcpy(e2.Tx[0].name,"enen"); e2.Tx[0].tel=1324456;

strcpy(e2.Tx[1].name,"cheng"); e2.Tx[1].tel=15679456;

strcpy(e2.Tx[2].name,"chengyi"); e2.Tx[2].tel=15679456;

OutPut(&e2,1);

struct empl e[2]={{"Mary","English",1985,4,17,},{2345,"Mike","English",66,"C",79}};

OutPut(ss,2);

struct student *pstu;

pstu=(student *)malloc(sizeof(student));

strcpy(pstu->name,"Jone");pstu->num=999;

strcpy( pstu->sco[0].course,"English"); pstu->sco[0].grade=66;

strcpy( pstu->sco[1].course,"Java"); pstu->sco[1].grade=63;

OutPut(pstu,1);

free(pstu);

getchar();

return 0;

}

void OutPut(struct empl *ps, int n){

int i,j;

for(i=0;i<n;i++){

printf("姓名=%s 工作=%s \n",ps->name,ps->job);

printf("出生年月=%d-%d-%d\n",ps->bday.year,ps->bday.month,ps->bday.day);

for (j=0;j<3;j++)

{

printf("姓名=%s，电话=%d \n",ps->Tx[j].name,ps->Tx[j].tel);

}

printf("\n\n");

ps++;

}