复利计算--单元测试

对我们和复利计算程序，写单元测试。 

   有哪些场景？

   期待的返回值

   写测试程序。

   运行测试。

测试计算是否正确：

@Test
    public void test0() {//测单利终值
        double money=1000000.0;
        int years=30;
        double r=0.03;
        double sum;
        sum = money + money * years * r;
         Assert.assertEquals(1900000,sum, 1.0);
    }
    @Test
    public void test1(){//测复利终值
        double money=1000000.0;
        int years=30;
        double r=0.03;
        double N=1;
        double sum;
        for (int i = 1; i <= years; i++) {
            N = (1 + r) * N;
        }
        sum = N * money;
        Assert.assertEquals(2427262,sum, 1.0);
    }
    @Test
    public void test2(){//测本金
         double N = 1, money;
         double sum=3000000;
         int years=30;
         double r=0.03;
         for (int i = 1; i <= years; i++) {
             N = (1 + r) * N;
         }
         money = sum / N;
         Assert.assertEquals(1235960,money, 1.0);
    }      

  不清楚究竟怎样做，都是跟着同学的教导做的，不太明白

@Test
    public void test0() {//测单利终值
        double money=1000000.0;
        int years=30;
        double r=0.03;
        double sum;
        sum = money + money * years * r;
         Assert.assertEquals(1900000,sum, 1.0);
    }
    @Test
    public void test1(){//测复利终值
        double money=1000000.0;
        int years=30;
        double r=0.03;
        double N=1;
        double sum;
        for (int i = 1; i <= years; i++) {
            N = (1 + r) * N;
        }
        sum = N * money;
        Assert.assertEquals(2427262,sum, 1.0);
    }
    @Test
    public void test2(){//测本金
         double N = 1, money;
         double sum=3000000;
         int years=30;
         double r=0.03;
         for (int i = 1; i <= years; i++) {
             N = (1 + r) * N;
         }
         money = sum / N;
         Assert.assertEquals(1235960,money, 1.0);
    }