On January 21, Beijing time, the fourth round of the Australian Open men's singles was contested, and the No. 5 seed Rublev and the No. 10 seed De Minaur met. The two sides staged a five-set battle in this match, and Rublev gave away an egg in the deciding set, and finally narrowly defeated the local darling De Minaur 3-2 and successfully reached the quarterfinals of the Australian Open men's singles.
In the fourth game of the first set, Rublev broke serve to take a 3-1 lead. In the seventh game, Rublev lost his serve, and De Minaur then held serve to tie it at 4-4. In the 10th game, Rublev made a crucial break at the end of the set to win the first set 6-4.
In the second set, both sides held serve in the first 12 games, and the match was dragged into a tie-break. De Minaur was even better in the tie-break, winning the second set 7-5.
In the third set, De Minaur broke serve first in the second game, and in the ninth game, Rublev broke De Minaur's serve after breaking a set point, and then both sides held serve and the match went into a tie-break again. In the tie-break, De Minaur led all the way and won the third set 7-4.
In the second game of the fourth set, Rublev broke first, De Minaur broke Rublev's serve in the fifth game, and Rublev broke again in the sixth game to lead his opponent 4-2. In the ninth game, Rublev scored four consecutive points to hold serve and drag the game into the deciding set 6-3.
In the deciding set, Rublev broke De Minaur's serve three times in a row, and in the sixth game, he saved three break points to hold serve in the tiebreaker 6-0.
In a match that lasted 4 hours and 14 minutes, Rublev defeated De Minaur 6-4, 6-7, 6-7, 6-3, 6-0 to reach the quarterfinals of the Australian Open for the second year in a row. It was the 10th time in his career that Rublev had reached the quarter-finals of a Grand Slam, having failed to go any further in the previous nine. In the quarter-finals, Rublev will face No. 4 seed Sinner.