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java bom 檔案讀取_java – 如何解析包含BOM的XML檔案?

該HTTP伺服器正在以GZIP形式發送内容(Content-Encoding:gzip;如果您不知道這意味着什麼,請參閱

http://en.wikipedia.org/wiki/HTTP_compression),是以您需要将aUrl.openStream()包裝在GZIPInputStream中,它将為您解壓縮它.例如:

builder.build(new GZIPInputStream(aUrl.openStream()));

根據後續評論編輯添加:如果您事先不知道URL是否為GZIPped,您可以這樣寫:

private InputStream openStream(final URL url) throws IOException

{

final URLConnection cxn = url.openConnection();

final String contentEncoding = cxn.getContentEncoding();

if(contentEncoding == null)

return cxn.getInputStream();

else if(contentEncoding.equalsIgnoreCase("gzip")

|| contentEncoding.equalsIgnoreCase("x-gzip"))

return new GZIPInputStream(cxn.getInputStream());

else

throw new IOException("Unexpected content-encoding: " + contentEncoding);

}

(警告:未經測試)然後使用:

builder.build(openStream(aUrl.openStream()));

.這基本上等同于上面的内容 – aUrl.openStream()被明确記錄為aUrl.openConnection().getInputStream()的簡寫 – 除了它在決定是否在GZIPInputStream中包裝流之前檢查Content-Encoding頭. .