感謝你先閱讀這篇文章。我通常用Perl編寫代碼，但我将轉向Python，我正試圖用下面的腳本應付過去。在
我有一個大的文本檔案，其格式如下。。。在2014 Apr 11 07:14:03.155 sectorBLAH
Interestingcontent
Interesting1 = 843
Interesting2 = 56
ReallyInteresting = 1
Interesting3 = N/A
2014 Apr 11 07:14:04.189 sectorBLAH
Interestingcontent
Interesting1 = 7843
Interesting2 = 656
ReallyInteresting = 0
Interesting3 = 5
這個序列會持續一段時間。
我希望做的是建立一個xls檔案，在我浏覽這個長清單時填充它。基本上，我希望找到“reallyinterest”字元串并捕獲它的值“0”或“1”，然後将該值發送到xls中的第2列。同時，在xls的第1列中，我希望釋出與“reallyinterest”字元串組的輸出相關聯的時間戳，有點像這樣。。。在
^{pr2}$
我寫了下面的代碼，但是我認為我的行和列被覆寫了。在import re
import xlwt
f = open("C:\Results\Logging.txt", "r")
book = xlwt.Workbook(encoding="utf-8")
sheet1 = book.add_sheet("New Sheet 1")
sheet2 = book.add_sheet("New Sheet 2")
searchlines = f.readlines()
searchstrings = ['ReallyInteresting =']
timestampline = None
timestamp = None
f.close()
a = 0
tot = 0
row1 = 1
row2 = 1
while a
for i, line in enumerate(searchlines):
for word in searchstrings:
if word in line:
timestampline = searchlines[i-4]
for l in searchlines[i:i+1]: print timestampline,l,
row1 +1
sheet1.write(0, row1, timestampline)
for i in line:
str = timestampline
match = re.search(r'\d{2}:\d{2}:\d{2}.\d{3}', ' ')
if match:
print '\t',match.group(),'\t',searchstrings[a]
row2 +1
sheet2.write(0, row2, searchstrings[a])
tot = tot+1
break
print 'total count for', '"',searchstrings[a],'"', 'is', tot
tot = 0
a = a+1
book.save("New_Excel.xls")
任何指導都将不勝感激。在
再次感謝，
米克