python實作3個人石頭剪刀布_剪刀石頭布-Python 3-初學者

I'm suppose to simulate a rock paper scissors game and this is what I have so far. It's not letting me input letters into the scoregame function. How can I fix this?

def scoregame(player1, player2):

if player1 == R and player2 == R:

scoregame = "It's a tie, nobody wins."

if player1 == S and player2 == S:

scoregame == "It's a tie, nobody wins."

if player1 == P and player2 == P:

scoregame = "It's a tie, nobody wins."

if player1 == R and player2 == S:

scoregame = "Player 1 wins."

if player1 == S and player2 == P:

scoregame = "Player 1 wins."

if player1 == P and player2 == R:

scoregame = "Player 1 wins."

if player1 == R and player2 == P:

scoregame == "Player 2 wins."

if player1 == S and player2 == R:

scoregame == "Player 2 wins."

if player1 == P and player2 == S:

scoregame = "Player 2 wins."

print(scoregame)

解決方案

You need to test against strings; you are now testing against variable names:

if player1 == 'R' and player2 == 'R':

but you can simplify the case where both players picked the same option by testing if they are equal:

if player1 == player2:

scoregame = "It's a tie, nobody wins."

Next, I'd use a mapping, a dictionary, to codify what beats what:

beats = {'R': 'S', 'S': 'P', 'P': 'R'}

if beats[player1] == player2:

scoregame = "Player 1 wins."

else:

scoregame = "Player 2 wins."

Now your game can be tested in just 2 tests. All put together:

def scoregame(player1, player2):

beats = {'R': 'S', 'S': 'P', 'P': 'R'}

if player1 == player2:

scoregame = "It's a tie, nobody wins."

elif beats[player1] == player2:

scoregame = "Player 1 wins."

else:

scoregame = "Player 2 wins."

print(scoregame)