傳送門

題意:
思路:
#include<cstdio>
#include<iostream>
#include<cstring>
#include<math.h>
#define ll long long
using namespace std;
double pi = acos(-1);
int main()
{
int t;
cin>>t;
while(t--)
{
double w,d;
cin>>w>>d;
double a = min(w,d),b = sqrt(pow(w,2)+pow(d,2));
ll ans = 0;
for(int i = 0; i <= 2; i++)
{
if(pi-i*a>=0)
ans = max(ans,(ll)(i*2+(ll)((pi-i*a)/b)*3.0));
if(pi-i*b>=0)
ans = max(ans,(ll)(i*3+(ll)((pi-i*b)/a)*2.0));
}
cout<<ans+4<<endl;
}
}