程式設計将二進制IP位址轉換成十進制

/******************************************************************
* Name: IP Address
* Funcion: To convert binary numbers to decimal numbers
* Input: 0000 0011 1000 0000 1111 1111 1111 1111
* Output: 3.128.255.255
**********************************************************************/
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<iostream>
#include<assert.h>
using namespace std;
void convert(char input[],unsigned char output[])//這裡的output必須為無符号型，否則必然出錯
{

    int count = -1,i;
    for( i = 0; i < 32; i++ )
    {
        if( i % 8 == 0 )
        count++;
        if( input[i] == '1' )
        {
            switch( i % 8 )
            {
                case 0:
                output[count] += 128;
                break;
                case 1:
                output[count] += 64;
                break;
                case 2:
                output[count] += 32;
                break;
                case 3:
                output[count] += 16;
                break;
                case 4:
                output[count] += 8;
                break;
                case 5:
                output[count] += 4;
                break;
                case 6:
                output[count] += 2;
                break;
                case 7:
                output[count] += 1;
                break;
                default:
                break;
            }
        }
    }
}
/************************************
增加難度 輸入和輸出都有句點分割  輸入輸出均表示為點分形式
************************************/
void binaryStringToInt(char binary[],int *data)
{
    int n=strlen(binary);
    for(int i=0;i<n;i++)
    {
        *data+=(binary[i]-'0')<<n-i-1;   //記得要  -'0' 謹記
    }
}
void test1()
{
    char i[]="11011";
    int d=0;
    binaryStringToInt(i,&d);
    cout<<"d= "<<d<<endl;
}
int  IP_convert(char input[],char output[])
{
    assert(NULL!=input);
    assert(NULL!=output);
    int count=0;
    char temp[50]={0};
    //char *s=strtok(input, '.');  謹記：strtok second  parameter is "" instead of ''
    char *s=strtok(input, ".");
    if(s==NULL)
    {
        cout<<"input error"<<endl;
        return -1;
    }
    while(s != NULL)
    {
        //cout<<s<<endl;
        binaryStringToInt(s,&count);   //求二進制字元串對應的整數值
        //cout<<"count= "<<count<<endl;
        itoa(count,temp,10);  //将得到的數字轉化為字元串
        count=0;                //一定要記得count  清零
        strcat(output,temp);   //連接配接到目的字元串
        strcat(output,".");    // 每一段添加一個點，但是最後會多一個點

        s = strtok(NULL, ".");   //繼續分割元字元串
    }
    int i=0;
    while(output[i]!='\0')i++;
    output[--i]='\0';  //消除最後多餘的句點
    return 0;
}
void test()
{
    char input[32];
    unsigned char output[4]={0};
    gets(input);
    convert(input,output);
    printf( "%d.%d.%d.%d\n", output[0], output[1], output[2], output[3] );
    cout<<"---------------------------------"<<endl;
}
int main()
{
    //test1();
    char i[]="00001101.00001111.00000001.00001010";
    char o[10]={0};
    IP_convert(i,o);
    puts(o);

    return 0;
}