UVA-Ancient Cipher

Ancient Roman empire had a strong government system with various departments, including a secret

service department. Important documents were sent between provinces and the capital in encrypted

form to prevent eavesdropping. The most popular ciphers in those times were so called substitution

cipher and permutation cipher.

Substitution cipher changes all occurrences of each letter to some other letter. Substitutes for all

letters must be different. For some letters substitute letter may coincide with the original letter. For

example, applying substitution cipher that changes all letters from ‘A’ to ‘Y’ to the next ones in the

alphabet, and changes ‘Z’ to ‘A’, to the message “VICTORIOUS” one gets the message “WJDUPSJPVT”.

Permutation cipher applies some permutation to the letters of the message. For example, applying

the permutation ⟨2, 1, 5, 4, 3, 7, 6, 10, 9, 8⟩ to the message “VICTORIOUS” one gets the message

“IVOTCIRSUO”.

It was quickly noticed that being applied separately, both substitution cipher and permutation

cipher were rather weak. But when being combined, they were strong enough for those times. Thus,

the most important messages were first encrypted using substitution cipher, and then the result was

encrypted using permutation cipher. Encrypting the message “VICTORIOUS” with the combination of

the ciphers described above one gets the message “JWPUDJSTVP”.

Archeologists have recently found the message engraved on a stone plate. At the first glance it

seemed completely meaningless, so it was suggested that the message was encrypted with some substitution

and permutation ciphers. They have conjectured the possible text of the original message that

was encrypted, and now they want to check their conjecture. They need a computer program to do it,

so you have to write one.

Input

Input file contains several test cases. Each of them consists of two lines. The first line contains the

message engraved on the plate. Before encrypting, all spaces and punctuation marks were removed, so

the encrypted message contains only capital letters of the English alphabet. The second line contains

the original message that is conjectured to be encrypted in the message on the first line. It also contains

only capital letters of the English alphabet.

The lengths of both lines of the input file are equal and do not exceed 100.

Output

For each test case, print one output line. Output ‘YES’ if the message on the first line of the input file

could be the result of encrypting the message on the second line, or ‘NO’ in the other case.

Sample Input

JWPUDJSTVP

VICTORIOUS

MAMA

ROME

HAHA

HEHE

AAA

AAA

NEERCISTHEBEST

SECRETMESSAGES

Sample Output

YES

NO

YES

YES

NO

隻要第一行中每種字母出現的次數在第二行中能找到一種字母出現的順序與其相等即可，沒有字母和順序要求。 不需要知道加密方式，加密方式是随機的。

題目看了好久沒看懂。。。

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>

using namespace std;

int main()
{
    char ch1[];
    char ch2[];
    int str1[];
    int str2[];
    int i;
    while(scanf("%s",ch1)==)
    {
        scanf("%s",ch2);
        memset(str1,,sizeof(str1));
        memset(str2,,sizeof(str2));
        int len1=strlen(ch1),len2=strlen(ch2);
        for(i=;i<len1;i++)
        {
            str1[ch1[i]-'A']++;
        }
        for(i=;i<len2;i++)
        {
            str2[ch2[i]-'A']++;
        }
        sort(str1,str1+);
        sort(str2,str2+);
        for(i=;i<;i++)
        {
            if(str1[i]!=str2[i])
            {
                break;
            }
        }
        if(i>=)
        {
            printf("YES\n");
        }
        else
        {
            printf("NO\n");
        }
    }
    return ;
}