1065 A+B and C (64bit) (20分)
思路
這道題的難點并不隻是相加可能導緻資料資料溢出。更重要的是,提供的輸入範圍裡,263根本就不在long long的範圍内。long long的範圍是到263-1。
也就是說,從儲存輸入這一步開始,就已經隻能用string類型了。
但是和C++不同,python3的int是無上限的(微笑)。
當然啦,C++也是可以做這道題的,隻不過大概得用string寫個循環來計算就是了。
代碼
times=int(input())
lst=[]
for i in range(times):
lst.append(list(map(int,input().split())))
print('Case #%d: '%(i+1),end='')
if lst[i][0]+lst[i][1]>lst[i][2]:
print('true')
else:
print('false')
題目
Given three integers A, B and C in [−263,263], you are supposed to tell whether A+B>C.
Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false