題目描述:
算法思想:同二叉樹的後序周遊類似
/*
// Definition for a Node.
class Node {
public:
int val;
vector<Node*> children;
Node() {}
Node(int _val, vector<Node*> _children) {
val = _val;
children = _children;
}
};
*/
class Solution {
public:
vector<int> res;
vector<int> postorder(Node* root) {
if(!root)
return res;
for(Node* child:root->children){
postorder(child);
}
res.push_back(root->val);
return res;
}
};
/*
// Definition for a Node.
class Node {
public:
int val;
vector<Node*> children;
Node() {}
Node(int _val, vector<Node*> _children) {
val = _val;
children = _children;
}
};
*/
class Solution {
public:
vector<int> postorder(Node* root) {
vector<int> res;
stack<Node*> s;
if(root==NULL)
return res;
s.push(root);
while(!s.empty()){//讓棧中始終隻存在一層節點
Node* now=s.top();
s.pop();
for(int i=0;i<now->children.size();i++){
s.push(now->children[i]);
}
res.push_back(now->val);
}
reverse(res.begin(),res.end());
return res;
}
};