本文執行個體講述了python讀寫二進制檔案的方法。分享給大家供大家參考。具體如下：
初學python，現在要讀一個二進制檔案，查找doc隻發現 file提供了一個read和write函數，而且讀寫的都是字元串，如果隻是讀寫char等一個位元組的還行，要想讀寫如int,double等多位元組數 據就不友善了。在網上查到一篇貼子，使用struct子產品裡面的pack和unpack函數進行讀寫。下面就自己寫代碼驗證一下。
>>> from struct import *
>>> file = open(r"c:/debug.txt", "wb")
>>> file.write(pack("idh", 12345, 67.89, 15))
>>> file.close()
接着再将其讀進來
>>> file = open(r"c:/debug.txt", "rb")
>>> (a,b,c) = unpack("idh",file.read(8+8+2))
>>> a,b,c
(12345, 67.890000000000001, 15)
>>> print a,b,c
12345 67.89 15
>>> file.close()
在操作過程中需要注意資料的size
注意 wb,rb中的b字，一定不可以少
方法1：
myfile=open('c:\\t','rb')
s=myfile.read(1)
byte=ord(s) #将一個位元組 讀成一個數
print hex(byte) #轉換成16進制的字元串
方法2
import struct
myfile=open('c:\\t','rb').read(1)
print struct.unpack('c',myfile)
print struct.unpack('b',myfile)
寫入
To open a file for binary writing is easy, it is the same way you do for reading, just change the mode into “wb”.
file = open("test.bin","wb")
But, how to write the binary byte into the file?You may write it straight away with hex code like this:
file.write("\x5F\x9D\x3E") file.close()
Now, check it out with hexedit,
hexedit test.bin
You will see this:
00000000 5F 9D 3E _.> 00000020 00000040
Now, open the file to append more bytes:
file = open("test.bin","ab")
What if I want to store by bin value into a stream and write it one short?s ="\x45\xF3" s = s + "%c%c" % (0x45,0xF3) file.write(s) file.close()
Any convenient ways if I can obtained a hex string, and want to convert it back to binary format?Yes, you just need to import binascii
import binascii hs="5B7F888489FEDA" hb=binascii.a2b_hex(hs) file.write(hb) file.close()
希望本文所述對大家的Python程式設計有所幫助。
本文标題: python讀寫二進制檔案的方法
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