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迪傑斯特拉算法求單源最短路徑[c++實作]

算法分析與設計課的期末考試題:

請程式設計實作單元最短路徑問題的求解方法,并編寫主程式調用該算法解決如下問題,求下圖中的1号頂點到2、3、4、5、6号頂點的最短路徑。

迪傑斯特拉算法求單源最短路徑[c++實作]
迪傑斯特拉算法求單源最短路徑[c++實作]
#include <stdio.h>
#include <stdlib.h>

typedef int Vertex;
#define x 10000 
#define size 6

int Graph[size][size] =


{
	x, 1, 12, x, x, x,
	x, x, 9, 3, x, x, 
	x, x, x, x, 5, x, 
	x, x, 4, x, 13, 15, 
	x, x, x, x, x, 4, 
	x, x, x, x, x, x, 
};
int Graph_Dist[size] = { x,x,x,x,x,x };
int Graph_Path[size] = { -1,-1,-1,-1,-1,-1 };
int Graph_Order[size] = { 0 };

void
Dijkstra(Vertex V0)
{
	Vertex V, W;
	int Order;
	Graph_Path[V0 - 1] = 0;
	Graph_Dist[V0 - 1] = 0;
	Graph_Order[V0 - 1] = 1;
	for (Order = 1; Order <= size; Order++)
	{
		for (V = 0; V < size; V++)
		{
			if (Graph_Order[V] == Order)
			{
				for (W = 0; W<size; W++)
				{
					if (Graph[V][W]!=x&&Graph_Dist[W] > Graph_Dist[V] + Graph[V][W])
						
					{
						Graph_Dist[W] = Graph_Dist[V] + Graph[V][W];
						Graph_Path[W] = V+1;
						Graph_Order[W] = Order + 1;
					}
				}
			}

		}
	}
}

void printarray(int a[]){
    int i =0;
	for (i = 1; i < size; i++)
		printf("%d ", a[i]);
}

void main()
{
	Dijkstra(1);

	printarray(Graph_Dist);

}
           

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