1.結構體名傳遞的也隻是副本
2.結構體指針做形參 實參傳遞結構體名位址 才是位址傳遞
#include<iostream>
using namespace std;
struct node
{
int age;
node(){age=0;}
node(int age){this->age=age;}
};
void add1(node no){
no.age++;
}
void add2(node* no){
no->age=no->age+1;//指針不能. 隻能用->
}
int main(){
freopen("input.txt","r",stdin);
node n1;
n1.age=10;
//結構體名傳遞的也隻是副本
add1(n1);
cout<<n1.age<<endl;
//結構體指針做形參 實參傳遞結構體名位址 才是位址傳遞
add2(&n1);
cout<<n1.age<<endl;
return 0;
}

#include<iostream>
#include<vector>
using namespace std;
void Clear(vector<int> v){
v.clear();
cout<<"函數内:"<<v.size()<<endl;
}
int main(){
vector<int> vi;
vi.push_back(1);
vi.push_back(2);
vi.push_back(3);
cout<<"Clear前:";
cout<<vi.size()<<endl;
Clear(vi);
cout<<"Clear後:";
cout<<vi.size()<<endl;
return 0;
}