如何找到一個數組裡面重複次數最多的數

#include 
  <
  iostream
  >
  
#include 
  <
  string
  >
  
#include 
  <
  iomanip
  >
  


  using
   
  namespace
   std;

  struct
   box
{
    
  int
   number;
    
  int
   chongfu;
};

  void
   show(
  int
   x[],
  int
   y);

  void
   show_struct(box x[],
  int
   y);

  int
   main()
{
    
  int
   test[
  10
  ]
  =
  {
  2
  ,
  3
  ,
  1
  ,
  1
  ,
  6
  ,
  65
  ,
  4
  ,
  6
  ,
  8
  ,
  8
  };
    
  for
   (
  int
   i
  =
  0
  ;i
  <
  10
  ;i
  ++
  )
    {
        
  for
   (
  int
   j
  =
  i
  +
  1
  ;j
  <
  10
  ;j
  ++
  )
        {
            
  if
   (test[i]
  >
  test[j])
            {
                
  int
   t;
                t
  =
  test[i];
                test[i]
  =
  test[j];
                test[j]
  =
  t;
            }
        }
    }
    box b[
  10
  ];
    
  for
   (
  int
   i
  =
  0
  ;i
  <
  10
  ;i
  ++
  )
    {
        b[i].chongfu
  =
  1
  ;
    }
    
  int
   c
  =
  0
  ;
    
  for
   (
  int
   i
  =
  0
  ;i
  <
  10
  ;i
  ++
  )
    {
        
  if
  (test[i]
  ==
  test[i
  +
  1
  ])
        {
            b[c].number
  =
  test[i];
            b[c].chongfu
  +=
  1
  ;
        }
        
  else
  
        {
            b[c].number
  =
  test[i];
            
  ++
  c;
        }


    }
    
  for
   (
  int
   i
  =
  0
  ;i
  <
  10
  ;i
  ++
  )
    {
        
  for
   (
  int
   j
  =
  i
  +
  1
  ;j
  <
  10
  ;j
  ++
  )
        {
            
  if
   (b[i].chongfu
  <
  b[j].chongfu)
            {
                box temp;
                temp
  =
  b[i];
                b[i]
  =
  b[j];
                b[j]
  =
  temp;

            }
        }
    }
    show(test,
  10
  );
    show_struct(b,c);
    
  return
   
  0
  ;
}


  void
   show(
  int
   x[],
  int
   y)
{
    
  for
   (
  int
   i
  =
  0
  ;i
  <
  y;i
  ++
  )
    {
        cout
  <<
  x[i]
  <<
  "
   
  "
  ;
    }
    cout
  <<
  endl;
}

  void
   show_struct(box x[],
  int
   y)
{
    
  for
   (
  int
   i
  =
  0
  ;i
  <
  y;i
  ++
  )
    {
        cout
  <<
  "
  number:
  "
  <<
  x[i].number
  <<
  "
   chongfu:
  "
  <<
  x[i].chongfu
  <<
  endl;
    }
    
}
 
      

運作效果：

1 1 2 3 4 6 6 8 8 65

number:1 chongfu:2

number:2 chongfu:1

number:3 chongfu:1

number:4 chongfu:1

number:6 chongfu:2

number:8 chongfu:2

number:65 chongfu:1

請按任意鍵繼續. . .