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$row=mysql_num_rows($result);什麼意思,警告:mysqli_num_rows()期望參數1為mysqli_result,布爾值為...

$row=mysql_num_rows($result);什麼意思,警告:mysqli_num_rows()期望參數1為mysqli_result,布爾值為...

include 'openCon.php' ;

$sql = "SELECT id,price,table,unitTable,chair,unitChair,lightingFan,unitLightingFan,Decoration, unitDecoration FROM packagea";

$result = mysqli_query($conn,$sql) ;

if(mysqli_num_rows($result) > 0) {

while($row = mysqli_fetch_assoc($result))

{

$id = $row['id'];

$price = $row['price'];

$table = $row['table'];

$unitTable = $row['unitTable'];

$chair = $row['chair'];

$unitChair = $row['unitChair'];

$lightingFan = $row['lightingFan'];

$unitLightingFan = $row['unitLightingFan'];

$Decoration = $row['Decoration'];

$unitDecoration = $row['unitDecoration'];

echo "";

echo "";

echo "";

echo "";

echo "";

echo "";

echo "";

echo "";

echo "";

echo "";

}

}

?>Bil Price TableUnitChairUnitLighting & FanUnitDecorationUnit

$id$price$table$unitTable$Chair$unitChair$lightingFan$unitLightingFan$Decoration$unitDecoration

->I HAVE PROBLEM AT THIS LINE = if(mysqli_num_rows($result) > 0) {

What I have tried:

I HAVE TRY GOOGLE FOR THE SOLUTION BUT EVERYTHING I TRY IT DOESNT FIX MY ERROR

解決方案sql = "SELECT id,price,table,unitTable,chair,unitChair,lightingFan,unitLightingFan,Decoration, unitDecoration FROM packagea";

result = mysqli_query(

conn,