以下代碼展示:
往模型空間中添加一個圓。圓心為(100, 100, 0),半徑為20,圓所在平面為XOY平面。
設定圓的圖層、顔色、線型、線寬請參考文章AutoCAD .Net 建立直線Line
using Autodesk.AutoCAD.Runtime;
using Autodesk.AutoCAD.ApplicationServices;
using Autodesk.AutoCAD.DatabaseServices;
using Autodesk.AutoCAD.Geometry;
using Autodesk.AutoCAD.EditorInput;
using Autodesk.AutoCAD.Colors;
[CommandMethod("NewCircle")]
public static void NewCircle()
{
Document doc = Application.DocumentManager.MdiActiveDocument;
Database db = doc.Database;
using (Transaction tr = db.TransactionManager.StartTransaction())
{
//-------------------------------
// 擷取模型空間
//-------------------------------
BlockTable blockTbl = tr.GetObject(
db.BlockTableId, OpenMode.ForRead) as BlockTable;
BlockTableRecord modelSpace = tr.GetObject(
blockTbl[BlockTableRecord.ModelSpace], OpenMode.ForWrite) as BlockTableRecord;
//-------------------------------
// 建立圓
//-------------------------------
Circle circle = new Circle();
circle.Center = new Point3d(, , );
circle.Normal = new Vector3d(, , );
circle.Radius = ;
//-------------------------------
// 添加到模型空間并送出到資料庫
//-------------------------------
modelSpace.AppendEntity(circle);
tr.AddNewlyCreatedDBObject(circle, true);
tr.Commit();
}
}
Circle.Normal 指定圓所在平面的法向量。
AutoCAD .Net API 中沒有提供求過3點圓的方法。
附上在2維平面内求過三點圓的方法
/// <summary>
/// 求過平面3點的圓
/// (x1, y1) --- 點1
/// (x2, y2) --- 點2
/// (x3, y3) --- 點3
/// (cx, cy) --- 求出的圓心坐标
/// radius --- 求出的圓心半徑
/// 傳回值:
/// 存在則傳回true
/// 不存在則傳回false
/// </summary>
public static bool CircleFrom3Points(
double x1, double y1,
double x2, double y2,
double x3, double y3,
out double cx, out double cy, out double radius)
{
double a = x1 - x2;
double b = y1 - y2;
double c = x1 - x3;
double d = y1 - y3;
double e = ((x1 * x1 - x2 * x2) + (y1 * y1 - y2 * y2)) / ;
double f = ((x1 * x1 - x3 * x3) + (y1 * y1 - y3 * y3)) / ;
double det = b * c - a * d;
if (Math.Abs(det) < )
{
cx = ;
cy = ;
radius = ;
return false;
}
else
{
cx = -(d * e - b * f) / det;
cy = -(a * f - c * e) / det;
radius = Math.Sqrt(
(x1 - cx) * (x1 - cx) + (y1 - cy) * (y1 - cy));
return true;
}
}