1~100之和
let xx = function sum(num){
if(num<=1){
return 1;
}
return num + sum(num - 1);
}
xx(100);
斐波那契數列
1 1 2 3 5 8 13 傳回目前位的數
let getCurrent = function aa(current){
if(current <= 2) return 1;
return aa(current - 1) + aa(current - 2);
}
getCurrent(6)