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二分搜尋樹02:二分搜尋樹的應用

基于二分搜尋樹的集合實作(Set)

不能添加重複元素

集合是有序的,效率高

interface Set<E>{

    void add(E e);
    void remove(E e);
    boolean contains(E e);
    int getSize();
    boolean isEmpty();
}

class BSTSet<E extends Comparable<E>> implements Set<E>{

    private BinarySearchTree bst;

    public BSTSet(){

        bst = new BinarySearchTree();
    }

    @Override
    public int getSize(){

        return bst.size();
    }

    @Override
    public boolean isEmpty(){

        return bst.isEmpty();
    }

    @Override
    public void add(E e){

        bst.add(e);
    }

    @Override
    public void remove(E e){

        bst.remove(e);
    }

    @Override
    public boolean contains(E e){

        return bst.contains(e);
    }
}

class BinarySearchTree<E extends Comparable<E>> {

    private class Node{

        public E e;
        public Node leftNext;
        public Node rightNext;

        private Node(E e){

            this.e = e;
            leftNext = null;
            rightNext = null;
        }
    }

    private Node root;
    private int size;

    public BinarySearchTree(){

        root = null;
        size = 0;
    }

    public int size(){

        return size;
    }

    public boolean isEmpty(){

        return size == 0;
    }

    public void add(E e) {

        root = add(root, e);
    }

    private Node add(Node root, E e){

        if (root == null){

            size++;

            return new Node(e);
        }

        if (root.e.compareTo(e) < 0){
            root.rightNext = add(root.rightNext, e);
        }
        else if (root.e.compareTo(e) > 0) {
            root.leftNext = add(root.leftNext, e);
        }

        return root;
    }

    public E removeMin(){

        E value = Min();
        root = removeMin(root);

        return value;
    }

    private Node removeMin(Node root){

        if (root.leftNext == null){

            Node newRoot = root.rightNext;
            root.rightNext = null;
            size--;

            return newRoot;
        }

        root.leftNext = removeMin(root.leftNext);

        return root;
    }

    public void remove(E e){

        root = remove(root, e);
    }

    private Node remove(Node root, E e){

        if (root == null){
            return null;
        }

        if (root.e.compareTo(e) < 0){

            root.rightNext = remove(root.rightNext, e);
            return root;
        }
        else if (root.e.compareTo(e) > 0){

            root.leftNext = remove(root.leftNext, e);
            return root;
        }
        else {

            if (root.leftNext == null) {

                Node newRoot = root.rightNext;
                root.rightNext = null;
                size--;

                return newRoot;
            } else if (root.rightNext == null) {

                Node newRoot = root.leftNext;
                root.leftNext = null;
                size--;

                return newRoot;
            } else {

                Node newRoot = Min(root.rightNext);
                newRoot.rightNext = removeMin(root.rightNext);
                newRoot.leftNext = root.leftNext;
                root.leftNext = null;
                root.rightNext = null;

                return newRoot;
            }
        }
    }

    public boolean contains(E e){

        return contains(root, e);
    }

    private boolean contains(Node root, E e){

        if (root == null) {
            return false;
        }

        if (root.e.compareTo(e) == 0){
            return true;
        }
        else if (root.e.compareTo(e) > 0){
            return contains(root.leftNext, e);
        }
        else {
            return contains(root.rightNext, e);
        }
    }

    public E Min(){

        return Min(root).e;
    }

    private Node Min(Node root){

        if (root == null){
            return null;
        }

        if (root.leftNext == null){
            return root;
        }

        return Min(root.leftNext);
    }
}
           

基于連結清單的集合實作

集合是無序的
interface Set<E>{

    void add(E e, int index);
    void remove(int index);
    boolean contains(E e);
    int getSize();
    boolean isEmpty();
}

class LinkedListSet<E> implements Set<E>{

    private LinkedList linkedList;

    public LinkedListSet(){

        linkedList = new LinkedList<>();
    }

    @Override
    public int getSize(){

        return linkedList.size();
    }

    @Override
    public boolean isEmpty(){

        return linkedList.isEmpty();
    }

    @Override
    public void add(E e, int index){

        if (!linkedList.contains(e)) {
            linkedList.add(e, index);
        }
    }

    @Override
    public void remove(int index){

        linkedList.remove(index);
    }

    @Override
    public boolean contains(E e){

        return linkedList.contains(e);
    }
}

class LinkedList<E>{

    class Node{

        public E e;
        public Node next;

        public Node(E e, Node next){

            this.e = e;
            this.next = next;
        }

        public Node(){

            this.next = null;
        }
    }

    private Node dummyHead;
    private int size;

    public LinkedList(){

        dummyHead = new Node();
        size = 0;
    }

    public int size(){

        return size;
    }

    public boolean isEmpty(){

        return isEmpty();
    }

    private Node getPrevNode(int index){

        if (index < 0 || index > size){
            throw new IllegalArgumentException("索引不合法");
        }

        if (index == 0){
            return dummyHead;
        }

        return getPrevNode(index - 1).next;
    }

    public void add(E e, int index){

        Node prev = getPrevNode(index);

        prev.next = new Node(e, prev.next);
        size++;
    }

    public E remove(int index){

        if (index == size){

            throw new IllegalArgumentException("索引不合法");
        }

        Node prev = getPrevNode(index);

        Node temp = prev.next;
        prev.next = temp.next;
        temp.next = null;
        size--;

        return temp.e;
    }

    public boolean contains(E e){

        for (Node prev = dummyHead; prev.next != null; prev = prev.next) {

            if (prev.next.e.equals(e)){
                return true;
            }
        }

        return false;
    }
}
           

基于連結清單的映射實作(Map)

存儲(鍵,值)資料對的資料結構,根據鍵尋找值

無序

interface Map<K, V>{

    void add(K key, V value);
    V remove(K key);
    boolean contains(K key);
    V get(K key);
    void set(K key, V value);
    int getSize();
    boolean isEmpty();
}

class LinkedListMap<K, V> implements Map<K, V>{

    class Node{

        public K key;
        public V value;
        public Node next;

        public Node(K key, V value, Node next){

            this.key = key;
            this.value = value;
            this.next = next;
        }

        public Node(){

            this(null, null, null);
        }
    }

    private Node dummyHead;
    private int size;

    public LinkedListMap(){

        dummyHead = new Node();
        size = 0;
    }

    @Override
    public int getSize(){

        return size;
    }

    @Override
    public boolean isEmpty(){

        return size == 0;
    }

    private Node getNode(K key){

        Node cur = dummyHead.next;

        while (cur != null){

            if (cur.key.equals(key)){
                return cur;
            }
            cur = cur.next;
        }

        return null;
    }

    @Override
    public boolean contains(K key){

        return getNode(key) != null;
    }

    @Override
    public V get(K key){

        Node res = getNode(key);
        return res == null ? null : res.value;
    }

    @Override
    public void add(K key, V value){

        Node res = getNode(key);

        if (res == null){
            dummyHead.next = new Node(key, value, dummyHead.next);
        }

        res.value = value;
    }

    @Override
    public void set(K key, V value) {

        Node res = getNode(key);

        if (res == null){
            throw new IllegalArgumentException("沒有這個鍵");
        }

        res.value = value;
    }

    @Override
    public V remove(K key){

        Node prev = dummyHead;

        while (prev.next != null){

            if (prev.next.key.equals(key)){

                Node temp = prev.next;
                prev.next = temp.next;
                temp.next = null;
                size--;

                return temp.value;
            }

            prev = prev.next;
        }

        return null;
    }
}
           
拓展:用哈希表實作的無序集合和映射,效率比二分搜尋樹更高

基于二分搜尋樹的映射實作

interface Map<K, V>{

    void add(K key, V value);
    V remove(K key);
    boolean contains(K key);
    V get(K key);
    void set(K key, V value);
    int getSize();
    boolean isEmpty();
}

class BSTMap<K extends Comparable<K>, V> implements Map<K, V>{

    class Node{

        public K key;
        public V value;
        public Node leftNext;
        public Node rightNext;

        public Node(K key, V value){

            this.key = key;
            this.value = value;
            leftNext = null;
            rightNext = null;
        }
    }

    private Node root;
    private int size;

    public BSTMap(){

        root = null;
        size = 0;
    }

    @Override
    public int getSize(){

        return size;
    }

    @Override
    public boolean isEmpty(){

        return size == 0;
    }


    private Node getNode(Node root, K key){

        if (root == null){
            return null;
        }

        if (root.key.compareTo(key) == 0){
            return root;
        }
        else if (root.key.compareTo(key) > 0){
            return getNode(root.leftNext, key);
        }
        else {
            return getNode(root.rightNext, key);
        }
    }

    @Override
    public boolean contains(K key){

        return getNode(root, key) != null;
    }

    @Override
    public V get(K key){

        Node res = getNode(root, key);

        return res == null ? null : res.value;
    }

    @Override
    public void add(K key, V value){

        root = add(root, key, value);
    }

    private Node add(Node root, K key, V value){

        if (root == null){

            size++;
            return new Node(key, value);
        }

        if (root.key.compareTo(key) > 0){
            root.leftNext = add(root.leftNext, key, value);
        }
        else if (root.key.compareTo(key) < 0){
            root.rightNext = add(root.rightNext, key, value);
        }
        else {
            root.value = value;
        }

        return root;
    }

    @Override
    public void set(K key, V value) {

        Node res = getNode(root, key);

        if (res == null){
            throw new IllegalArgumentException("鍵值不存在");
        }
        else {
            res.value = value;
        }
    }

    private Node Min(Node root){

        if (root.leftNext == null){
            return root;
        }

        return Min(root.leftNext);
    }

    private Node removeMin(Node root){

        if (root.leftNext == null){

            Node newRoot = root.rightNext;
            root.rightNext = null;
            size--;

            return newRoot;
        }

        root.leftNext = removeMin(root.leftNext);

        return root;
    }

    @Override
    public V remove(K key){

        Node res = getNode(root, key);

        if (res == null){
            throw new IllegalArgumentException("鍵值不存在");
        }

        root = remove(root, key);

        return res.value;
    }

    private Node remove(Node root, K key){

        if (root.key.compareTo(key) > 0){

            root.leftNext = remove(root.leftNext, key);
            return root;
        }
        else if (root.key.compareTo(key) < 0){

            root.rightNext = remove(root.rightNext, key);
            return root;
        }
        else {

            if (root.leftNext == null) {

                Node newRoot = root.rightNext;
                root.rightNext = null;
                size--;

                return newRoot;
            }
            else if (root.rightNext == null) {

                Node newRoot = root.leftNext;
                root.leftNext = null;
                size--;

                return newRoot;
            }
            else {

                Node min = Min(root.rightNext);
                min.rightNext = removeMin(root.rightNext);
                min.leftNext = root.leftNext;
                root.leftNext = null;
                root.rightNext = null;

                return min;
            }
        }
    }
}
           

複雜度分析