Python3不需要uuid：導入/usr/local/lib/python3.x/site-packages/uuid.py提示if not 0 time_low 32L錯誤

這錯誤．．．

Traceback (most recent call last):
  File "/home/aaa.py", line 17, in <module>
    import requests
  File "/usr/local/lib/python3.5/site-packages/requests/__init__.py", line 53, in <module>
    from .packages.urllib3.contrib import pyopenssl
  File "/usr/local/lib/python3.5/site-packages/requests/packages/__init__.py", line 27, in <module>
    from . import urllib3
  File "/usr/local/lib/python3.5/site-packages/requests/packages/urllib3/__init__.py", line 8, in <module>
    from .connectionpool import (
  File "/usr/local/lib/python3.5/site-packages/requests/packages/urllib3/connectionpool.py", line 41, in <module>
    from .request import RequestMethods
  File "/usr/local/lib/python3.5/site-packages/requests/packages/urllib3/request.py", line 7, in <module>
    from .filepost import encode_multipart_formdata
  File "/usr/local/lib/python3.5/site-packages/requests/packages/urllib3/filepost.py", line 4, in <module>
    from uuid import uuid4
  File "/usr/local/lib/python3.5/site-packages/uuid.py", line 138
    if not 0 <= time_low < 1<<32L:
                                ^
SyntaxError: invalid syntax      

怎麼辦？網上搜尋了半天沒找到辦法，後來幹脆解除安裝，問題解決！

sudo pip3 uninstall uuid