文章目錄
一、misc1
二、答題步驟
1.偏移128
總結
題目連結:
https://adworld.xctf.org.cn/task/task_list?type=misc&number=1&grade=1&page=3每兩個分組十六進制,轉成十進制後-128(偏移量為128)
再轉成ascii碼得到flag:DDCTF{9af3c9d377b61d269b11337f330c935f}
python腳本
import re
s = 'd4e8e1f4a0f7e1f3a0e6e1f3f4a1a0d4e8e5a0e6ece1e7a0e9f3baa0c4c4c3d4c6fbb9e1e6b3e3b9e4b3b7b7e2b6b1e4b2b6b9e2b1b1b3b3b7e6b3b3b0e3b9b3b5e6fd'
num = re.findall('\w{2}' ,s)
flag = ''
for i in num:
ch = chr(int(i,16)-128)
flag += ch
print(flag)
或
cipher ="d4e8e1f4a0f7e1f3a0e6e1f3f4a1a0d4e8e5a0e6ece1e7a0e9f3baa0c4c4c3d4c6fbb9e1e6b3e3b9e4b3b7b7e2b6b1e4b2b6b9e2b1b1b3b3b7e6b3b3b0e3b9b3b5e6fd"
print(’’.join([chr(int(cipher[i:i + 2], 16) - 128) for i in range(0,len(cipher), 2)]))
- 16進制
- ascii
- python