zip函數接受任意多個可疊代對象作為參數,将對象中對應的元素打包成一個 tuple
,然後傳回一個可疊代的zip對象.
這個可疊代對象可以使用循環的方式列出其元素
若多個可疊代對象的長度不一緻,則所傳回的清單與長度最短的可疊代對象相同.
用法1:用兩個清單生成一個zip對象
例1
>>> a1=[1,2,3]
>>> a2=[4,5,6]
>>> a3=[7,8,9]
>>> a4=["a","b","c","d"]
>>> zip1=zip(a1,a2,a3)
>>> print(zip1)
<zip object at 0x7f5a22651c08>
>>> for i in zip1:
... print(i)
...
(1, 4, 7)
(2, 5, 8)
(3, 6, 9)
例2
>>> zip2=zip(a1,a2,a4)
>>> print(zip2)
<zip object at 0x7f5a22651d48>
>>> for j in zip2:
... print(j)
...
(1, 4, 'a')
(2, 5, 'b')
(3, 6, 'c')
例3
>>> zip3=zip(a4)
>>> print(zip3)
<zip object at 0x7f5a22651d08>
>>> for i in zip3:
... print(i)
...
('a',)
('b',)
('c',)
('d',)
例4
>>> zip4=zip(*a4 *3)
>>>
>>> print(zip4)
<zip object at 0x7f5a22651f08>
>>> for j in zip4:
... print(j)
...
('a', 'b', 'c', 'd', 'a', 'b', 'c', 'd', 'a', 'b', 'c', 'd')
用法2:二維矩陣變換(矩陣的行列互換)
>>> l1=[[1,2,3],[4,5,6],[7,8,9]]
>>> print([[j[i] for j in l1] for i in range(len(l1[0])) ])
[[1, 4, 7], [2, 5, 8], [3, 6, 9]]
>>> zip(*l1)
<zip object at 0x7f5a22651f88>
>>> for i in zip(*l1):
... print(i)
...
(1, 4, 7)
(2, 5, 8)
(3, 6, 9)