[劍指offer] 合并兩個排序的連結清單

題目描述

輸入兩個單調遞增的連結清單，輸出兩個連結清單合成後的連結清單，當然我們需要合成後的連結清單滿足單調不減規則。

解題思路

兩種解法：遞歸和非遞歸

參考代碼

/*
public class ListNode {
    int val;
    ListNode next = null;

    ListNode(int val) {
        this.val = val;
    }
}*/
//遞歸解法
public class Solution {
    public ListNode Merge(ListNode list1,ListNode list2) {
        if(list1 == null)
            return list2;
        else if(list2 == null)
            return list1;
        ListNode mergehead = null;
        if(list1.val <= list2.val){
            mergehead = list1;
            mergehead.next = Merge(list1.next,list2);
        }else{
            mergehead = list2;
            mergehead.next = Merge(list1, list2.next);
        }
        return mergehead;
    }
}
//非遞歸解法
public class Solution {
    public ListNode Merge(ListNode list1,ListNode list2) {
        if(list1 == null)
            return list2;
        else if(list2 == null)
            return list1;
        ListNode mergehead = null;
        if(list1.val <= list2.val){
            mergehead = list1;
            list1 = list1.next;
        }else{
            mergehead = list2;
            list2 = list2.next;
        }
        ListNode cur = mergehead;
        while(list1 != null && list2 != null){
            if(list1.val <= list2.val){
                cur.next = list1;
                list1 = list1.next;
            }else{
                cur.next = list2;
                list2 = list2.next;
            }
            cur = cur.next;
        }
        if(list1 == null)
            cur.next = list2;
        else if(list2 == null)
            cur.next = list1;
        return mergehead;
    }
}