LeetCode - 22. Generate Parentheses 22. Generate Parentheses Problem's Link

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Mean: 

給定一個數n，輸出由2*n個'('和')'組成的字元串，該字元串符合括号比對規則.

analyse:

遞歸求解.

Time complexity: O(N)

view code

/**

* -----------------------------------------------------------------

* Copyright (c) 2016 crazyacking.All rights reserved.

*       Author: crazyacking

*       Date  : 2016-02-17-17.58

*/

#include <queue>

#include <cstdio>

#include <set>

#include <string>

#include <stack>

#include <cmath>

#include <climits>

#include <map>

#include <cstdlib>

#include <iostream>

#include <vector>

#include <algorithm>

#include <cstring>

using namespace std;

typedef long long(LL);

typedef unsigned long long(ULL);

const double eps(1e-8);

class Solution

{

public:

   vector<string> generateParenthesis(int n)

   {

       vector<string> res;

       recursive(res,"",n,0);

       return res;

   }

   void recursive(vector<string>& v,string str,int n,int m)

       if(n==0 && m==0)

       {

           v.push_back(str);

           return;

       }

       if(m>0)

           recursive(v,str+")",n,m-1);

       if(n>0)

           recursive(v,str+"(",n-1,m+1);

};

int main()

   Solution solution;

   int n;

   while(cin>>n)

       auto ans=solution.generateParenthesis(n);

       for(auto p:ans)

           cout<<p<<endl;

       cout<<"End."<<endl;

   return 0;

}

/*